Optimal. Leaf size=221 \[ -\frac{b^{3/2} (5 a B e-7 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}+\frac{b (5 a B e-7 A b e+2 b B d)}{\sqrt{d+e x} (b d-a e)^4}+\frac{5 a B e-7 A b e+2 b B d}{3 (d+e x)^{3/2} (b d-a e)^3}+\frac{5 a B e-7 A b e+2 b B d}{5 b (d+e x)^{5/2} (b d-a e)^2}-\frac{A b-a B}{b (a+b x) (d+e x)^{5/2} (b d-a e)} \]
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Rubi [A] time = 0.228903, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.152, Rules used = {27, 78, 51, 63, 208} \[ -\frac{b^{3/2} (5 a B e-7 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}+\frac{b (5 a B e-7 A b e+2 b B d)}{\sqrt{d+e x} (b d-a e)^4}+\frac{5 a B e-7 A b e+2 b B d}{3 (d+e x)^{3/2} (b d-a e)^3}+\frac{5 a B e-7 A b e+2 b B d}{5 b (d+e x)^{5/2} (b d-a e)^2}-\frac{A b-a B}{b (a+b x) (d+e x)^{5/2} (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 27
Rule 78
Rule 51
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{A+B x}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )} \, dx &=\int \frac{A+B x}{(a+b x)^2 (d+e x)^{7/2}} \, dx\\ &=-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{(2 b B d-7 A b e+5 a B e) \int \frac{1}{(a+b x) (d+e x)^{7/2}} \, dx}{2 b (b d-a e)}\\ &=\frac{2 b B d-7 A b e+5 a B e}{5 b (b d-a e)^2 (d+e x)^{5/2}}-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{(2 b B d-7 A b e+5 a B e) \int \frac{1}{(a+b x) (d+e x)^{5/2}} \, dx}{2 (b d-a e)^2}\\ &=\frac{2 b B d-7 A b e+5 a B e}{5 b (b d-a e)^2 (d+e x)^{5/2}}-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{2 b B d-7 A b e+5 a B e}{3 (b d-a e)^3 (d+e x)^{3/2}}+\frac{(b (2 b B d-7 A b e+5 a B e)) \int \frac{1}{(a+b x) (d+e x)^{3/2}} \, dx}{2 (b d-a e)^3}\\ &=\frac{2 b B d-7 A b e+5 a B e}{5 b (b d-a e)^2 (d+e x)^{5/2}}-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{2 b B d-7 A b e+5 a B e}{3 (b d-a e)^3 (d+e x)^{3/2}}+\frac{b (2 b B d-7 A b e+5 a B e)}{(b d-a e)^4 \sqrt{d+e x}}+\frac{\left (b^2 (2 b B d-7 A b e+5 a B e)\right ) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{2 (b d-a e)^4}\\ &=\frac{2 b B d-7 A b e+5 a B e}{5 b (b d-a e)^2 (d+e x)^{5/2}}-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{2 b B d-7 A b e+5 a B e}{3 (b d-a e)^3 (d+e x)^{3/2}}+\frac{b (2 b B d-7 A b e+5 a B e)}{(b d-a e)^4 \sqrt{d+e x}}+\frac{\left (b^2 (2 b B d-7 A b e+5 a B e)\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{e (b d-a e)^4}\\ &=\frac{2 b B d-7 A b e+5 a B e}{5 b (b d-a e)^2 (d+e x)^{5/2}}-\frac{A b-a B}{b (b d-a e) (a+b x) (d+e x)^{5/2}}+\frac{2 b B d-7 A b e+5 a B e}{3 (b d-a e)^3 (d+e x)^{3/2}}+\frac{b (2 b B d-7 A b e+5 a B e)}{(b d-a e)^4 \sqrt{d+e x}}-\frac{b^{3/2} (2 b B d-7 A b e+5 a B e) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}\\ \end{align*}
Mathematica [C] time = 0.0416859, size = 94, normalized size = 0.43 \[ \frac{(5 a B e-7 A b e+2 b B d) \, _2F_1\left (-\frac{5}{2},1;-\frac{3}{2};\frac{b (d+e x)}{b d-a e}\right )+\frac{5 (a B-A b) (b d-a e)}{a+b x}}{5 b (d+e x)^{5/2} (b d-a e)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.023, size = 403, normalized size = 1.8 \begin{align*} -{\frac{2\,Ae}{5\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}+{\frac{2\,Bd}{5\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}+{\frac{4\,Abe}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{2\,aBe}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{2\,Bbd}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-6\,{\frac{A{b}^{2}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}+4\,{\frac{Beab}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}+2\,{\frac{B{b}^{2}d}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}-{\frac{A{b}^{3}e}{ \left ( ae-bd \right ) ^{4} \left ( bex+ae \right ) }\sqrt{ex+d}}+{\frac{Bea{b}^{2}}{ \left ( ae-bd \right ) ^{4} \left ( bex+ae \right ) }\sqrt{ex+d}}-7\,{\frac{A{b}^{3}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+5\,{\frac{Bea{b}^{2}}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+2\,{\frac{B{b}^{3}d}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.56726, size = 3629, normalized size = 16.42 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.21396, size = 587, normalized size = 2.66 \begin{align*} \frac{{\left (2 \, B b^{3} d + 5 \, B a b^{2} e - 7 \, A b^{3} e\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )} \sqrt{-b^{2} d + a b e}} + \frac{\sqrt{x e + d} B a b^{2} e - \sqrt{x e + d} A b^{3} e}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}} + \frac{2 \,{\left (15 \,{\left (x e + d\right )}^{2} B b^{2} d + 5 \,{\left (x e + d\right )} B b^{2} d^{2} + 3 \, B b^{2} d^{3} + 30 \,{\left (x e + d\right )}^{2} B a b e - 45 \,{\left (x e + d\right )}^{2} A b^{2} e - 10 \,{\left (x e + d\right )} A b^{2} d e - 6 \, B a b d^{2} e - 3 \, A b^{2} d^{2} e - 5 \,{\left (x e + d\right )} B a^{2} e^{2} + 10 \,{\left (x e + d\right )} A a b e^{2} + 3 \, B a^{2} d e^{2} + 6 \, A a b d e^{2} - 3 \, A a^{2} e^{3}\right )}}{15 \,{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left (x e + d\right )}^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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